document.write( "Question 33053: x squared + 12x = 27 \n" ); document.write( "
Algebra.Com's Answer #19540 by sarah_adam(201)\"\" \"About 
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\"x%5E2%2B12x-27\"=0
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "here a=1 b = 12 c=-27
\n" ); document.write( "therfore substituting those values
\n" ); document.write( "\"x+=+%28-12+%2B-+sqrt%28+12%5E2-4%2A1%2A%28-27%29+%29%29%2F%282%2A1%29+\"
\n" ); document.write( "\"x+=+%28-12+%2B-+sqrt%28+144%2B108+%29%29%2F%282%2A1%29+\"
\n" ); document.write( "\"x+=+%28-12+%2B-+sqrt%28+252+%29%29%2F2+\"
\n" ); document.write( "\"x+=+%28-12+%2B-+2%2Asqrt%28+63+%29%29%2F2+\"
\n" ); document.write( "x = (-6 +- sqrt(63)) \r
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