document.write( "Question 265829: A 25-ft by 35-ft rectangular swimming pool is surrounded by a walkway of uniform width. If the total area o the walkway is 396ft^2, how wide is the walkway? \n" ); document.write( "
Algebra.Com's Answer #195399 by mananth(16946)\"\" \"About 
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A 25-ft by 35-ft rectangular swimming pool is surrounded by a walkway of uniform width. If the total area o the walkway is 396ft^2, how wide is the walkway?\r
\n" ); document.write( "\n" ); document.write( "let the width of walkaway be x\r
\n" ); document.write( "\n" ); document.write( "length of swimming pool + walkaway = 35+2x
\n" ); document.write( "width of swimming + walkaway = 25+2x\r
\n" ); document.write( "\n" ); document.write( "Total area = ( 35+2x)(25+2x)\r
\n" ); document.write( "\n" ); document.write( "total area - swimming pool area = walkaway area.\r
\n" ); document.write( "\n" ); document.write( " ( 35+2x)(25+2x)- 25*35= 396\r
\n" ); document.write( "\n" ); document.write( "875+70x+50x+4x^2 -875= 396
\n" ); document.write( "70x+50x +4x^2=396
\n" ); document.write( "4x^2+120x-396=0
\n" ); document.write( "x^2+30x-99=0
\n" ); document.write( "x^2+33x-3x-99=0
\n" ); document.write( "x(x+33)-3(x+33)=0
\n" ); document.write( "(x-3)(x+33)=0\r
\n" ); document.write( "\n" ); document.write( "x=3 The width of the walaway = 3 feet
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