document.write( "Question 265831: I attempted this problem but I am not sure of the answer. Can someone check to see if my answer is correct. Thanks.
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Algebra.Com's Answer #195398 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
\"36y%5E4%2B36y%5E3%2B6y-1=+6y%5E2%2B6y-1\"
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document.write( "Get 0 on the right:\r\n" );
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document.write( "\"36y%5E4%2B36y%5E3-6y%5E2=0\"\r\n" );
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document.write( "factor out \"6y%5E2\" on the left\r\n" );
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document.write( "\"6y%5E2%286y%5E2%2B6y-1%29=0\"\r\n" );
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document.write( "Set the first factor =0\r\n" );
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document.write( "\"6y%5E2=0\"\r\n" );
document.write( "\"y%5E2=0\"\r\n" );
document.write( "\"y=0\", that's one solution.\r\n" );
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document.write( "Set the second factor = 0\r\n" );
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document.write( "\"6y%5E2%2B6y-1=0\"\r\n" );
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document.write( "That trinomial will not factor. So we\r\n" );
document.write( "use the quadratic formula:\r\n" );
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document.write( "\"y+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" \r\n" );
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document.write( "\"y+=+%28-%286%29+%2B-+sqrt%28+%286%29%5E2-4%2A%286%29%2A%28-1%29+%29%29%2F%282%2A%286%29%29+\" \r\n" );
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document.write( "\"y+=+%28-6+%2B-+sqrt%28+36%2B24%29%29%2F12+\"\r\n" );
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document.write( "\"y+=+%28-6+%2B-+sqrt%2860%29%29%2F12+\"\r\n" );
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document.write( "\"y+=+%28-6+%2B-+sqrt%284%2A15%29%29%2F12+\"\r\n" );
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document.write( "\"y+=+%28-6+%2B-+2%2Asqrt%2815%29%29%2F12+\"\r\n" );
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document.write( "\"y+=+%282%28-3+%2B-+sqrt%2815%29%29%29%2F12+\"\r\n" );
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document.write( "\"y+=+%28cross%282%29%28-3+%2B-+sqrt%2815%29%29%29%2Fcross%2812%29%5B6%5D+\"\r\n" );
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document.write( "\"y=%28-3+%2B-+sqrt%2815%29%29%2F6\"\r\n" );
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document.write( "So there are three solutions:\r\n" );
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document.write( "\"y=0\", \"y=%28-3+%2B+sqrt%2815%29%29%2F6\", and \"y=%28-3+-+sqrt%2815%29%29%2F6\"\r\n" );
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document.write( "Edwin
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