document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=265838>Question 265838</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 89 octane gas is made by mixing 87 octane gas and 92 octane gas.  How many gallons of the 87 octane gas and 92 octane gas should be used to make 500 gallons of the 89 octane gas?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #195394 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=195394\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 89 octane gas is made by mixing 87 octane gas and 92 octane gas. How many gallons of the 87 octane gas and 92 octane gas should be used to make 500 gallons of the 89 octane gas?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "octane + octane = octane<BR>\n" );
document.write( "87x + 92(500-x) = 89*500<BR>\n" );
document.write( "87x = 92*500 - 92x = 89*500<BR>\n" );
document.write( "-5x = -3*500<BR>\n" );
document.write( "x = 300 (# of gallons of 87 octane gas needed in the mixture)<BR>\n" );
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document.write( "500-x = 200 (# of gallons of 92 octain gas needed in the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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