document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33053>Question 33053</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x squared + 12x = 27 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19539 by </B><A HREF=/tutors/aboutme.mpl?userid=priya><B>priya(51)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=priya><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19539\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> R U SURE THE EQUATION IS X^2+12X =27,\r<BR>\n" );
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document.write( "I think the question should be x^2 +12 x = -27 or<BR>\n" );
document.write( "                                x^2 -12x = 27..<BR>\n" );
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document.write( "  if this right ...herez the answer,\r<BR>\n" );
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document.write( "First re-arrange the question in standard equation format..<BR>\n" );
document.write( " that is, x^2+12x= -27\r<BR>\n" );
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document.write( "as   x^2 +12x + 27 =0(  when u bring the 27 from the right of the equation to the left u've to change it's sign,hence -27 becomes +27)\r<BR>\n" );
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document.write( "then there is a short cut to find the value of x.\r<BR>\n" );
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document.write( "if the equation is in the standard form like x^2+ (y)x + c  = 0, where y is the co-efficient of x and c is an independent number.,<BR>\n" );
document.write( "then<BR>\n" );
document.write( "find  2 numbers that gives  \"c\" as product(that is when u multiply the numbers that would give u \"c\"),and the addition of the same 2 numbers gives the co-efficient of x(here y).<BR>\n" );
document.write( "  so here ...for 27,the multiples are 1*27,3*9,9*3<BR>\n" );
document.write( "now   1. take the first 2 numbers 1 & 27,when u add it does it give the co-efficient of x(here 12) no..<BR>\n" );
document.write( "2.so go to the next set of numbers- 3 & 9<BR>\n" );
document.write( "when u multiply these 2 numbers,it gives u 27 and when u add it ,it gives u 12(co-efficient of x).\r<BR>\n" );
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document.write( "so the numbers are 3 & 9.<BR>\n" );
document.write( "so u've to write the numbers as  (x+3)(x+9)= 0,therefore the values of x= -3 and -9..  </SPAN>\n" );
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