document.write( "Question 265761: n-2=4-2n please show work \n" ); document.write( "
Algebra.Com's Answer #195368 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"n-2=4-2n\"\r\n" );
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document.write( "add\"red%28%22%2B2%22%29\" to both sides \r\n" );
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document.write( "\"n-2\"\"red%28%22%2B2%22%29\"\"%22%22=4-2n\"\"red%28%22%2B2%22%29\"\r\n" );
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document.write( "The \"-2\" and the \"red%28%22%2B2%22%29\" cancel out on the left\r\n" );
document.write( "The \"4\" and the \"red%28%22%2B2%22%29\" combine to give 6 on the right:\r\n" );
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document.write( "\"n=6-2n\"\r\n" );
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document.write( "add\"red%28%22%2B%22%29\"\"red%28%222%22%29\"\"red%28%22n%22%29%29\" to both sides\r\n" );
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document.write( "\"n\"\"red%28%22%2B%22%29\"\"red%28%222%22%29\"\"red%28%22n%22%29%29\"\"%22=%22\"\"6-2n\"\"red%28%22%2B%22%29\"\"red%28%222%22%29\"\"red%28%22n%22%29%29\"\r\n" );
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document.write( "The terms on the left side combine to give \"3n\"\r\n" );
document.write( "The \"-2n\" and the \"red%28%22%2B%22%29\"\"red%28%222%22%29\"\"red%28%22n%22%29%29\"\r\n" );
document.write( "cancel out on the right, and you have this left:\r\n" );
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document.write( "\"3n=6\"\r\n" );
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document.write( "Now we divide both sides by the coefficient of n which is 3\r\n" );
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document.write( "\"%283n%29%2Fred%283%29=6%2Fred%283%29\"\r\n" );
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document.write( "The 3's on the left cancel and leaves n.\r\n" );
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document.write( "\"%28cross%283%29n%29%2Fred%28cross%283%29%29=6%2Fred%283%29\"\r\n" );
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document.write( "The 6 divides by 3 on the right and gives 2\r\n" );
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document.write( "\"n=2\"\r\n" );
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document.write( "Edwin
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