document.write( "Question 265742: Jason has some nickels and some dimes. The value of the coins is $1.65. There are 12 more nickels than dimes. How many of each coin does Jason have? \n" ); document.write( "
Algebra.Com's Answer #195360 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let represent the number of dimes. Then Let must be the number of nickels. Each of his dimes is worth 10 cents, so the value of his dimes is Let cents. Each nickel is worth 5 cents, so the value of the nickels is cents. Total value of his money is $1.65, which is to say 165 cents. Since he presumably has no coins other than the dimes and the nickels:\r
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\n" ); document.write( "\n" ); document.write( "Solve for to get the number of dimes, then add 12 to that to get the number of nickels. Check by adding up the amount of money that many coins represents -- it should work out to $1.65.\r
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