document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=265660>Question 265660</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you walk me thru this plz?\r<BR>\n" );
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document.write( "A circle of diameter 2 in. has its center at the center of a square of side 2 in. Find the area of the region that is inside the square and outside the circle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #195314 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=195314\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It's the area of the square minus the area of the circle.<BR>\n" );
document.write( "Area of the square = 2*2 = 4 sq units<BR>\n" );
document.write( "Area of the circle = pi*r^2 = pi sq units<BR>\n" );
document.write( "= 4 - pi<BR>\n" );
document.write( "=~ 0.8584 sq units<BR>\n" );
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