document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=265588>Question 265588</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A person climbs to the top of a mountain at the rate of 1.5 kilometers per hour and down the same way at a rate of 4.5 kilometers per hour.If he is gone for 6 hours, how far did he travel from camp to the top of the mountain?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #195294 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=195294\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "D=1.5T UP THE MOUNTAIN.<BR>\n" );
document.write( "D=4.5(6-T) DOWN THE MOUNTAIN<BR>\n" );
document.write( "SET THE DISTANCES EQUAL & SOLVE FOR THE TIME.<BR>\n" );
document.write( "1.5T=4.5(6-T)<BR>\n" );
document.write( "1.5T=27-4.5T<BR>\n" );
document.write( "1.5T+4.5T=27<BR>\n" );
document.write( "6T=27<BR>\n" );
document.write( "T=27/6<BR>\n" );
document.write( "T=4.5 HOURS FOR THE TIME GOING UP THE MOUNTAIN.<BR>\n" );
document.write( "D=1.5*4.5=6.75 MILES IS THE DISTANCE UP THE MOUNTAIN.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "6.75=4.5(6-4.5)<BR>\n" );
document.write( "6.75=4.5*1.5<BR>\n" );
document.write( "6.75=6.75 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );