document.write( "Question 265545: Find the equation of the line that contains the given point and has the given slope. Let y be the dependent variable and let x be the independent variable.
\n" ); document.write( "Point (1, 1), m = 4/5 \n" ); document.write( "
Algebra.Com's Answer #195291 by dabanfield(803)\"\" \"About 
You can put this solution on YOUR website!
Find the equation of the line that contains the given point and has the given slope. Let y be the dependent variable and let x be the independent variable.
\n" ); document.write( "Point (1, 1), m = 4/5 \r
\n" ); document.write( "\n" ); document.write( "The standard form of a line in slope-intercept form is y = m*x + b where m is the slope and b is the value of y where the line crosses the x-axis (that is when x=0).\r
\n" ); document.write( "\n" ); document.write( "In this case we have slope = 4/5 so the line looks like:\r
\n" ); document.write( "\n" ); document.write( "y = (4/5)*x + b\r
\n" ); document.write( "\n" ); document.write( "We still need to find the value for b. Since the point (1,1) is a point on the line we know when x = 1, then y = 1. Substituting these values for x and y in the equation above we have:\r
\n" ); document.write( "\n" ); document.write( "1 = (4/5)*1 + b
\n" ); document.write( "1 = 4/5 + b
\n" ); document.write( "b = 1 - 4/5 = 1/5\r
\n" ); document.write( "\n" ); document.write( "So the equation is: y = (4/5)*x + 1/5 \n" ); document.write( "
\n" );