document.write( "Question 33108: I am home-schooling this semester for the first time. I am using the curriculum from Alpha and Omega Academy (SOS Schoolhouse). I know I can do these problems, I am just missing some key factor.\r
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document.write( "The question is this:
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document.write( "Two years ago a father was four times as old as his son. Three years from now, the father will be only three times as old as the son. How old is each now?\r
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document.write( "I tried:
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document.write( "son=x
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document.write( "dad=4(x-2)\r
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document.write( "x + 4(x-2) = 3 + 3x
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document.write( "x + 4x - 8 = 3 +3x
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document.write( "5x -8 = 3+3x
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document.write( "2x=11
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document.write( "(As you can see, this is wrong.If you could help me with this one, I can get the rest, I hope. Thanks!!!!) \n" );
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Algebra.Com's Answer #19522 by mukhopadhyay(490)![]() ![]() ![]() You can put this solution on YOUR website! son' current age =x \n" ); document.write( "dad's age as of two years ago = 4(x-2) \n" ); document.write( "dad's age now = 4(x-2) + 2 \n" ); document.write( "4(x-2) + 2 + 3 = 3(x+3) \n" ); document.write( "=> 4x - 3 = 3x + 9 \n" ); document.write( "=> x = 12 \n" ); document.write( "Son is now 12 years old and dad is 42 years. \n" ); document.write( " |