document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=265514>Question 265514</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive even integers such that the sum of the first and second equals the sum of the third and -10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #195219 by </B><A HREF=/tutors/aboutme.mpl?userid=roseo><B>roseo(33)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=roseo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=195219\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x= the first even integer<BR>\n" );
document.write( "x+2 = the second even integer<BR>\n" );
document.write( "x+4 = the third even integer  (Because we know to get the next even integer we just add 2)<BR>\n" );
document.write( "Then the sum of the first two would be x+x+2 and the sum of the third and -10 would be x+4+(-10) or x-6 .<BR>\n" );
document.write( "Therefore we can write the equation<BR>\n" );
document.write( "x+x+2 = x-6<BR>\n" );
document.write( "Combining like terms on the left we have<BR>\n" );
document.write( "2x+2 = x-6<BR>\n" );
document.write( "Then subtract x from each side<BR>\n" );
document.write( "x+2 = -6 <BR>\n" );
document.write( "Then subtract 2 from each side so we have<BR>\n" );
document.write( "x=-8<BR>\n" );
document.write( "Then x+2 = -8+2 or -6<BR>\n" );
document.write( "and x+4 = -8+4 or -4.<BR>\n" );
document.write( "So your three consecutive integers are -8,-6, and-4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );