document.write( "Question 265459: x - 25y = 30 & y = -34x + 350 \n" ); document.write( "

Algebra.Com's Answer #195199 by roseo(33) $\"\"$ $\"About$

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Because one equation is already solved for y use that for substitution in the other equation.
\n" ); document.write( "x-25y=30
\n" ); document.write( "y=-34x + 350
\n" ); document.write( "x-25(-34x+350)=30
\n" ); document.write( "x+850x-8750=30
\n" ); document.write( "851x-8750=30
\n" ); document.write( "851x=8780
\n" ); document.write( "x=8780/851
\n" ); document.write( "Then substitute this value into either equation to find y. The second one looks the best.
\n" ); document.write( "y= -34(8780/851)+350
\n" ); document.write( "y= -3356/4255
\n" ); document.write( "y=-.787
\n" ); document.write( "x=8780/851
\n" ); document.write( "x = 10.317
\n" ); document.write( "When you gave the original problem the problem became much easier and the two equations that you should have written were
\n" ); document.write( "2A + 3B = 34 and
\n" ); document.write( "25A + 30 B = 350 Where A = the # of A bikes and B = the # of B bikes
\n" ); document.write( "then multiply the first by -10 so that you have
\n" ); document.write( "-20A - 30B = -340 and add that to the second
\n" ); document.write( "25A +30B = 350 and you have
\n" ); document.write( "5A = 10 and then
\n" ); document.write( "A = 2 and then 2(2)+3B = 34
\n" ); document.write( "so 4+3B = 34
\n" ); document.write( "3B = 30 and B = 10
\n" ); document.write( "(10.317,-.787) \n" ); document.write( "

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