document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=265456>Question 265456</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangular garden is 1 yard more than half the length.<BR>\n" );
document.write( "If the perimeter is 26 yards, find the length and width of the garden. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #195165 by </B><A HREF=/tutors/aboutme.mpl?userid=roseo><B>roseo(33)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=roseo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=195165\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Because the width is given in terms of the length, make the length = x and then the width would be 1+ 1/2 x.  Remember that the perimeter  is twice the length plus twice the width. Therefore,<BR>\n" );
document.write( "2x + 2(1 + 1/2 x) = 26<BR>\n" );
document.write( "2x + 2 +x = 26<BR>\n" );
document.write( "3x +2 = 26<BR>\n" );
document.write( "3x = 24<BR>\n" );
document.write( "x = 8<BR>\n" );
document.write( "So 8 yd. would be the length and 1 + 1/2 (8) = 5 yd. would be the width </SPAN>\n" );
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