document.write( "Question 265079: Solve for p
\n" );
document.write( "1/p+1/q=1/f
\n" );
document.write( "I came up with the lcm:fpq so now it turns into this:
\n" );
document.write( "fq/fpq+fp/fpq=pq/fpq
\n" );
document.write( "But I don't know where to go from there. I saw someone else just do this:
\n" );
document.write( "fq+fp=pq but it seemed confusing because I don't know what they did with the denominator \n" );
document.write( "
Algebra.Com's Answer #195155 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Solve for p \n" ); document.write( " \n" ); document.write( "the common denominator is pqf, multiply each term by pqf, this gets rid of the denominators, results: \n" ); document.write( "qf + pf = pq \n" ); document.write( ": \n" ); document.write( "Subtract qf from both sides \n" ); document.write( "pf = pq - qf \n" ); document.write( ": \n" ); document.write( "subtract pq from both sides \n" ); document.write( "pf - pq = -qf \n" ); document.write( ": \n" ); document.write( "Factor out p on the right \n" ); document.write( "p(f-q) = -qf \n" ); document.write( ": \n" ); document.write( "Divide both sides by (f-q), results \n" ); document.write( "p = \n" ); document.write( ": \n" ); document.write( "Did this make sense to you now?\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |