document.write( "Question 265079: Solve for p
\n" ); document.write( "1/p+1/q=1/f
\n" ); document.write( "I came up with the lcm:fpq so now it turns into this:
\n" ); document.write( "fq/fpq+fp/fpq=pq/fpq
\n" ); document.write( "But I don't know where to go from there. I saw someone else just do this:
\n" ); document.write( "fq+fp=pq but it seemed confusing because I don't know what they did with the denominator
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Algebra.Com's Answer #195155 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Solve for p
\n" ); document.write( "\"1%2Fp%2B1%2Fq=1%2Ff\"
\n" ); document.write( "the common denominator is pqf, multiply each term by pqf, this gets rid of the denominators, results:
\n" ); document.write( "qf + pf = pq
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\n" ); document.write( "Subtract qf from both sides
\n" ); document.write( "pf = pq - qf
\n" ); document.write( ":
\n" ); document.write( "subtract pq from both sides
\n" ); document.write( "pf - pq = -qf
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\n" ); document.write( "Factor out p on the right
\n" ); document.write( "p(f-q) = -qf
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\n" ); document.write( "Divide both sides by (f-q), results
\n" ); document.write( "p = \"-%28qf%29%2F%28f-q%29\"
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\n" ); document.write( "Did this make sense to you now?\r
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