document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=265441>Question 265441</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three times the ten's digit of a certain two-digit number is two more than 4 times the unit's digit. The difference of the original number and the number obtained by reversing the digit is two less than twice the sum of the digits. Find the original number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #195152 by </B><A HREF=/tutors/aboutme.mpl?userid=vksarvepalli><B>vksarvepalli(154)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vksarvepalli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=vksarvepalli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=195152\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the two digit number be xy  (x- tens digit & y- units digit)\r<BR>\n" );
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document.write( "so number value=10x+y\r<BR>\n" );
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document.write( "reversed digit is yx and its value is 10y+x\r<BR>\n" );
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document.write( "given 3x = 2+4y --------------1    (so x>y and also xy>yx)\r<BR>\n" );
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document.write( "and also given that \r<BR>\n" );
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document.write( " (10x+y)-(10y+x) = 2(x+y)-2\r<BR>\n" );
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document.write( "=> 9x-9y = 2x+2y-2<BR>\n" );
document.write( "=> 7x = 11y-2 ----------------2\r<BR>\n" );
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document.write( "multiply equation-1 by 7 and equation-2 by 3 and then subtract\r<BR>\n" );
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document.write( "we get 14+28y = 33y-6\r<BR>\n" );
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document.write( "=>   5y=20<BR>\n" );
document.write( "=>   y=4\r<BR>\n" );
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document.write( "and 3x=2+16=18\r<BR>\n" );
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document.write( "so x=6\r<BR>\n" );
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document.write( "so the two digit number is 64 </SPAN>\n" );
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