document.write( "Question 265350: Motorcycle travels 45/mph, walk 6/mph, if travel 25 miles in 2 hrs how far did motorcycle go before broke down? \r
\n" ); document.write( "\n" ); document.write( "Have m45/60+w6/60=25/2
\n" ); document.write( "=m45+w6=750=w6=750-m45=w=12.5-6.5m so
\n" ); document.write( "but onot sure of that and don't know how to formulate rest of problem. \n" ); document.write( "
Algebra.Com's Answer #195128 by mananth(16949)\"\" \"About 
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Motorcycle travels 45/mph, walk 6/mph, if travel 25 miles in 2 hrs how far did motorcycle go before broke down? \r
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\n" ); document.write( "\n" ); document.write( "let motorcycle be driven for x kms.
\n" ); document.write( "walking will be 25-x\r
\n" ); document.write( "\n" ); document.write( "distance/rate = time\r
\n" ); document.write( "\n" ); document.write( "x/45 is time driven\r
\n" ); document.write( "\n" ); document.write( "25-x/6 = time walked\r
\n" ); document.write( "\n" ); document.write( "x/45 + 25-x / 6= 2 270 LCD\r
\n" ); document.write( "\n" ); document.write( "6x+1125-45x = 270*2
\n" ); document.write( "-39x=540-1125
\n" ); document.write( "-39x=-585
\n" ); document.write( "x= -585 / -39\r
\n" ); document.write( "\n" ); document.write( "x=15 the motor cycle broke down after 15 kilometers
\n" ); document.write( "& he walked 10 kilometers\r
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