document.write( "Question 265347: The square of the first of three consecutive odd integers is 9 more than 6 times the sum of the second and the first. Find the numbers.
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Algebra.Com's Answer #195123 by mananth(16946)\"\" \"About 
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The square of the first of three consecutive odd integers is 9 more than 6 times the sum of the second and the first. Find the numbers.\r
\n" ); document.write( "\n" ); document.write( "let the numbers be x , x+2 , x+4 \r
\n" ); document.write( "\n" ); document.write( "(x+x+2+x+4)^2 = 6(x+x+2) +9
\n" ); document.write( "(3x+6)^2=12x=12+9
\n" ); document.write( "9x^2+36x+36=12x+3
\n" ); document.write( "9x^2+36x-12x+36-3=0
\n" ); document.write( "9x^2+24x+15=0 ( divide equation by3\r
\n" ); document.write( "\n" ); document.write( "3x^2+8x+5=0
\n" ); document.write( "3x^2+3x+5x+5=0
\n" ); document.write( "3x(x+1)+5(x+1)=0
\n" ); document.write( "(x+1)(3x+5)=0
\n" ); document.write( "x=-1
\n" ); document.write( "the numbers are -1 , +1, +3
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