document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=265344>Question 265344</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I begin to solve these equations? 1)  1/2x+5/8=3/4x                      2)  2x/4+x/5=7/10     3) -4(n+5)+3(2n-4)=5(n-4) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #195121 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=195121\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "I'll make a deal with you. I'll do the first one and see if you can do the others. OK?<BR>\n" );
document.write( "1) 1/2x+5/8=3/4x  This one is best done by getting rid of the fractions first. So multiply by 8. I'm assuming the equation is actually this: 1) 1/2(x)+5/8=3/4(x)<BR>\n" );
document.write( "4x+5=6x Now subtract 4x from both sides to get:<BR>\n" );
document.write( "5=2x Divide each side by 2 to result in:<BR>\n" );
document.write( "x=5/2 There we go. <BR>\n" );
document.write( "The whole objective in algebra is to get the x on one side by itself.<BR>\n" );
document.write( "RJ <BR>\n" );
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