document.write( "Question 4318: What is ln(ln X)=2 \n" ); document.write( "
Algebra.Com's Answer #1951 by rapaljer(4671)\"\" \"About 
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The inverse of \"ln+x+\" is \"e%5Ex\", and vice-versa. Because of this inverse definition, \"e%5E%28ln+x%29+=+x\" and also \"ln+e%5Ex+=+x+\". \r
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\n" ); document.write( "\n" ); document.write( "Therefore, in order to \"undo\" the first \"ln\", you must raise both sides of the equation as a power of e. In other words, write \r
\n" ); document.write( "\n" ); document.write( "\"ln%28ln+x%29+=+2\"
\n" ); document.write( "\"e%5Eln%28ln+x%29+=+e%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "So this simplifies to
\n" ); document.write( "\"ln+x+=+e%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Now, raise both sides as a power of e again:\r
\n" ); document.write( "\n" ); document.write( "\"ln+x+=+e%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"e%5Eln+x+=+e%5E%28e%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Final answer is \"+x+=+e%5E%28e%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 from SCC
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