document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=265288>Question 265288</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do I solve this linear probleam I'm confused  3x-4y=12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #195099 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=195099\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> IF you want to solve for y, then<BR>\n" );
document.write( "step 1 - subtract 3x to get<BR>\n" );
document.write( "-4y = -3x + 12<BR>\n" );
document.write( "step 2 - divide by -4 to get<BR>\n" );
document.write( "y = (3/4)x -3 </SPAN>\n" );
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