document.write( "Question 33090: A rectangular yard is surrounded by a fence that is 4 feet longer than it is wide. If the perimeter of the fence is 424 feet, what are the dimensions of the yard it encloses?\r
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Algebra.Com's Answer #19509 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Start with the formula for the perimeter of a rectangle.
\n" ); document.write( "\"P+=+2%28L%2BW%29\" But L = W+4 and P = 4254 feet, so:
\n" ); document.write( "\"424+=+2%28W%2B4%2BW%29\"
\n" ); document.write( "\"424+=+2%284%2B2W%29\"
\n" ); document.write( "\"424+=+8%2B4W\" Subtract 8 from both sides of the equation.
\n" ); document.write( "\"416+=+4W\" Divide both sides by 4.
\n" ); document.write( "\"104+=+W\"feet and
\n" ); document.write( "\"L+=+W%2B4\"
\n" ); document.write( "\"L+=+104+%2B+4\"
\n" ); document.write( "\"L+=+108\"feet
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