document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=265236>Question 265236</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What are the coterminal angles of:<BR>\n" );
document.write( "17pi/5<BR>\n" );
document.write( "67pi/2<BR>\n" );
document.write( "15pi/9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #195065 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=195065\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we know that every 2pi a full circle has been completed.<BR>\n" );
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document.write( "In terms of pi/5 a full circle is 10pi/5<BR>\n" );
document.write( "but we need 7pi/5 more. 5pi/5 = pi = 1/2 circle<BR>\n" );
document.write( "so we need 2pi/5 more.<BR>\n" );
document.write( "The terminal angle is 2pi/5.<BR>\n" );
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document.write( "In terms of pi/2 a full circle is 4pi/2<BR>\n" );
document.write( "16 circles = 64pi/2<BR>\n" );
document.write( "so we need 3pi/2 more.<BR>\n" );
document.write( "The terminal angle is -pi/2.<BR>\n" );
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document.write( "In terms of pi/9 a full circle is 18pi/9<BR>\n" );
document.write( "but this is 3pi/9 too much, so we come back 3pi/9 = pi/3<BR>\n" );
document.write( "The terminal angle is pi/3. </SPAN>\n" );
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