document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33063>Question 33063</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve equations with the following type of exponents?\r<BR>\n" );
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document.write( "2^2n-1=8^n+7\r<BR>\n" );
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document.write( "Thanks for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19505 by </B><A HREF=/tutors/aboutme.mpl?userid=sarah_adam><B>sarah_adam(201)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sarah_adam><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19505\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2^2n-1=8^n+7<BR>\n" );
document.write( "take logs on both sides<BR>\n" );
document.write( "(2n-1)log 2 = (n+7) log 8<BR>\n" );
document.write( "(2n-1)log 2 = (n+7) log(2^3) {8=2^3}<BR>\n" );
document.write( "(2n-1)log 2 = 3*(n+7)log 2 ( according to log a^b = blog a)<BR>\n" );
document.write( "cancelling log 2 on both sides<BR>\n" );
document.write( "(2n-1)= 3*(n+7)<BR>\n" );
document.write( "2n - 1 = 3n +21<BR>\n" );
document.write( "n = -22\r<BR>\n" );
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