document.write( "Question 265124: 28,000 is invested, part at 4% and the remainder at 10% annual interest. The interest earned by the two accounts is equal at the end of the year. How much was invested at 4%? \n" ); document.write( "
Algebra.Com's Answer #195037 by checkley77(12844)\"\" \"About 
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.10X=.04(28,000-X)
\n" ); document.write( ".10X=1.120-.04X
\n" ); document.write( ".10X+.04X=1,120
\n" ); document.write( ".14X=1,120
\n" ); document.write( "X=1,120/.14
\n" ); document.write( "X=8,000 AMOUNT INVESTED @ 10%.
\n" ); document.write( "28,000-8,000=20,000 AMOUNT INVESTED @ 4%.
\n" ); document.write( "PROOF:
\n" ); document.write( ".10*8,000=.04*20,000
\n" ); document.write( "800=800
\n" ); document.write( "
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