document.write( "Question 265124: 28,000 is invested, part at 4% and the remainder at 10% annual interest. The interest earned by the two accounts is equal at the end of the year. How much was invested at 4%? \n" ); document.write( "
Algebra.Com's Answer #195037 by checkley77(12844) ![]() You can put this solution on YOUR website! .10X=.04(28,000-X) \n" ); document.write( ".10X=1.120-.04X \n" ); document.write( ".10X+.04X=1,120 \n" ); document.write( ".14X=1,120 \n" ); document.write( "X=1,120/.14 \n" ); document.write( "X=8,000 AMOUNT INVESTED @ 10%. \n" ); document.write( "28,000-8,000=20,000 AMOUNT INVESTED @ 4%. \n" ); document.write( "PROOF: \n" ); document.write( ".10*8,000=.04*20,000 \n" ); document.write( "800=800 \n" ); document.write( " |