document.write( "Question 265143: How many liters of a 30% alcohol solution must be mixed with 80 liters of a 90% solution to get an 80% solution? \n" ); document.write( "
Algebra.Com's Answer #195013 by checkley77(12844)\"\" \"About 
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.90*80+.30x=.80(80+x)
\n" ); document.write( "72+.30x=64+.80x
\n" ); document.write( ".30x-.80x=64-72
\n" ); document.write( "-.50x=-8
\n" ); document.write( "x=-8/-.50
\n" ); document.write( "x=16 liters of 30% alcohol is used.
\n" ); document.write( "Proof:
\n" ); document.write( ".90*80+.30*16=.80(80+16)
\n" ); document.write( "72+4.8=.8*96
\n" ); document.write( "76.8=76.8\r
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