document.write( "Question 264958: Fifteen minutes after a boy left for school on his bike, his mother noticed that he left his term paper on the kitchen table. His mother left home, driving at a rate of 32 mph, to catch up to him. If he had been bicycling at a rate of 8 mph, how long did it take his mother to catch up with him? \n" ); document.write( "
Algebra.Com's Answer #194991 by ankor@dixie-net.com(22740)\"\" \"About 
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Fifteen minutes after a boy left for school on his bike, his mother noticed that he left his term paper on the kitchen table. His mother left home, driving at a rate of 32 mph, to catch up to him.
\n" ); document.write( " If he had been bicycling at a rate of 8 mph, how long did it take his mother to catch up with him?
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\n" ); document.write( "Change 15 min to .25 hrs
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\n" ); document.write( "Let t = travel time of the mother
\n" ); document.write( "then
\n" ); document.write( "(t+.25) = travel time of the boy
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\n" ); document.write( "When Mom catches boy they will have traveled the same distance,
\n" ); document.write( "write a distance equation Dist = speed * time
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\n" ); document.write( "Mom's dist = boy's dist
\n" ); document.write( "32t = 8(t+.25)
\n" ); document.write( "32t = 8t + 2
\n" ); document.write( "32t - 8t = 2
\n" ); document.write( "24t = 2
\n" ); document.write( "t = \"2%2F24\" * 60 = 5 minutes to catch him
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\n" ); document.write( "Check solution by finding the dist each traveled (boy's travel time 15 + 5 = 20 min)
\n" ); document.write( "5/60(32) = 2.67 mi
\n" ); document.write( "20/60(8) = 2.67 mi \n" ); document.write( "
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