document.write( "Question 265111: Why does a perfect square result from adding two successive rows of even and odd integers? Example: 1+2 plus 1+2+3 = 9
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Algebra.Com's Answer #194987 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let n = last number in first row\r
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\n" ); document.write( "\n" ); document.write( "If we generalize the problem, we get\r
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\n" ); document.write( "\n" ); document.write( "1+2+3+...+n
\n" ); document.write( "1+2+3+...+n+(n+1)\r
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\n" ); document.write( "\n" ); document.write( "Add the two rows to get\r
\n" ); document.write( "\n" ); document.write( "(1+2+3+...+n)+(1+2+3+...+n+(n+1))\r
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\n" ); document.write( "\n" ); document.write( "Now simplify:\r
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\n" ); document.write( "\n" ); document.write( "(1+1)+(2+2)+(3+3)+...+(n+n)+n+1\r
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\n" ); document.write( "\n" ); document.write( "2(1)+2(2)+2(3)+...+2(n)+n+1\r
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\n" ); document.write( "\n" ); document.write( "2(1+2+3+...+n)+n+1\r
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\n" ); document.write( "\n" ); document.write( "Now use the formula 1+2+3+...+n = n(n+1)/2\r
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\n" ); document.write( "\n" ); document.write( "2(n(n+1)/2)+n+1\r
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\n" ); document.write( "\n" ); document.write( "n(n+1)+n+1\r
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\n" ); document.write( "\n" ); document.write( "n^2+n+n+1\r
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\n" ); document.write( "\n" ); document.write( "n^2+2n+1\r
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\n" ); document.write( "\n" ); document.write( "(n+1)^2\r
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\n" ); document.write( "\n" ); document.write( "So this shows that the sum of 1+2+3+...+n and 1+2+3+...+n+(n+1) is a perfect square and it shows us that the perfect square is (n+1)^2\r
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\n" ); document.write( "\n" ); document.write( "In the case that n = 4, we get\r
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\n" ); document.write( "\n" ); document.write( "(1+2+3+4)+(1+2+3+4+5) = 10+15 = 25\r
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\n" ); document.write( "\n" ); document.write( "Take note that 25 = 5^2 = (4+1)^2 which confirms our answer.
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