document.write( "Question 265049: Fiona wants to buy a new house but she doesn't want a house with the numbers that are divisable by 3 or 5. If all the houses numbered between 100 and 150 inclusive are for sale how many houses can she choose from? \n" ); document.write( "
Algebra.Com's Answer #194973 by josmiceli(19441)\"\" \"About 
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The multiples of 3 that are included in
\n" ); document.write( "houses numbered 100-150 are:
\n" ); document.write( "34 x 3 = 102
\n" ); document.write( "35 x 3 = 105
\n" ); document.write( "36 x 3 = 108
\n" ); document.write( "up to:
\n" ); document.write( "50 x 3 = 150
\n" ); document.write( "And the multiples of 5 are:
\n" ); document.write( "20 x 5 = 100
\n" ); document.write( "21 x 5 = 105
\n" ); document.write( "22 x 5 = 110
\n" ); document.write( "up to
\n" ); document.write( "30 x 5 = 150
\n" ); document.write( "------------
\n" ); document.write( "I don't want to count house numbers twice, so
\n" ); document.write( "in the 1st list I'll pull out thoses divisible by 5
\n" ); document.write( "35 x 3
\n" ); document.write( "40 x 3
\n" ); document.write( "45 x 3
\n" ); document.write( "50 x 3
\n" ); document.write( "------------
\n" ); document.write( "The 1st list has \"50+-+34+%2B+1+=+17\" entries
\n" ); document.write( "I want to delete 4
\n" ); document.write( "\"17+-+4+=+13\"
\n" ); document.write( "The 2nd list has \"30+-+20+%2B+1+=+11\" entries
\n" ); document.write( "\"13+%2B+11+=+24\"
\n" ); document.write( "There are 24 house numbers she doesn't want
\n" ); document.write( "\"150+-+100+%2B+1+=+51\" possible numbers
\n" ); document.write( "\"51+-+24+=+27\"
\n" ); document.write( "She can choose from 27 houses
\n" ); document.write( "Hope I got it right!\r
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