document.write( "Question 33061: 2) A painter leans a ladder against one wall of a house. The ladder is 24 ft long. The base of the ladder is 18 ft from the house. How high is the wall?\r
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\n" ); document.write( "\n" ); document.write( "A) 126 ft
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\n" ); document.write( "\n" ); document.write( "B) 21 ft
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\n" ); document.write( "\n" ); document.write( "C) 7.938 ft
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\n" ); document.write( "\n" ); document.write( "D) 15.875 ft \r
\n" ); document.write( "\n" ); document.write( "Please let me know how you solved this so I can help myself.
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Algebra.Com's Answer #19496 by priya(51)\"\" \"About 
You can put this solution on YOUR website!
The ladder leans against the wall and makes it a right-angled triangle.
\n" ); document.write( "The wall and the ground are at right-angle (90 degrees)and the ladder is the
\n" ); document.write( "hypotunes of the triangle.\r
\n" ); document.write( "\n" ); document.write( "There is a formula to find the side of the triangle(either the base or the height).
\n" ); document.write( "Let H be the height(unknown here) ,B be the base(18ft) and L be the hypotunes(24 ft),
\n" ); document.write( "therefore,
\n" ); document.write( "H= SQRT(L^2-B^2)\r
\n" ); document.write( "\n" ); document.write( "Now substitute the values .
\n" ); document.write( "this gives you- H = SQRT(24^2-18^2)
\n" ); document.write( " = SQRT(576-324)
\n" ); document.write( " = SQRT(252)
\n" ); document.write( " =15.875 ft..that is the height of the wall.\r
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