document.write( "Question 264816: 1/4(-2/3)+1/2 what the simplest to modify in simplest terms need examples thanks \r
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Algebra.Com's Answer #194905 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
I read this to be:\r
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\n" ); document.write( "\n" ); document.write( "(1/4) * (-2/3) + (1/2)\r
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\n" ); document.write( "\n" ); document.write( "first multiply the 2 fractions together to get:\r
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\n" ); document.write( "\n" ); document.write( "(-2/12) + (1/2)\r
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\n" ); document.write( "\n" ); document.write( "since -2/12 reduces to -1/6, then simplify this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "(-1/6) + (1/2)\r
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\n" ); document.write( "\n" ); document.write( "since 2 goes into 6 3 times, then multiply your second fraction by 3/3 to get:\r
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\n" ); document.write( "\n" ); document.write( "(-1/6) + (3/6)\r
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\n" ); document.write( "\n" ); document.write( "combine terms under the common denominator to get:\r
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\n" ); document.write( "\n" ); document.write( "(-1+3)/6)\r
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\n" ); document.write( "\n" ); document.write( "simplify to get:\r
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\n" ); document.write( "\n" ); document.write( "2/6\r
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\n" ); document.write( "\n" ); document.write( "simply further to get:\r
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\n" ); document.write( "\n" ); document.write( "1/3\r
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\n" ); document.write( "\n" ); document.write( "your fraction should simplify to 1/3\r
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\n" ); document.write( "\n" ); document.write( "a simpler way might be:\r
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\n" ); document.write( "\n" ); document.write( "original equation is:\r
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\n" ); document.write( "\n" ); document.write( "(1/4) * (-2/3) + (1/2)\r
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\n" ); document.write( "\n" ); document.write( "multiply first 2 terms to get:\r
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\n" ); document.write( "\n" ); document.write( "(-2/12) + (1/2)\r
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\n" ); document.write( "\n" ); document.write( "multiply second term by 6/6 to get:\r
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\n" ); document.write( "\n" ); document.write( "(-2/12) + (6/12)\r
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\n" ); document.write( "\n" ); document.write( "combine under common denominator to get:\r
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\n" ); document.write( "\n" ); document.write( "(-2+6)/12\r
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\n" ); document.write( "\n" ); document.write( "simplify to get:\r
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\n" ); document.write( "\n" ); document.write( "4/12\r
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\n" ); document.write( "\n" ); document.write( "divide numerator and denominator by 4 to get:\r
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\n" ); document.write( "\n" ); document.write( "1/3\r
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\n" ); document.write( "\n" ); document.write( "either way works.\r
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