document.write( "Question 264864: an airplane travels 900 miles from houston to miami in 6 hors against the wind.on its return trip, with the wind, it takes only 5 hours. find the rate of the airplane with no wind. find the rate of the wind \n" ); document.write( "
Algebra.Com's Answer #194896 by mananth(16946)![]() ![]() You can put this solution on YOUR website! an airplane travels 900 miles from houston to miami in 6 hors against the wind.on its return trip, with the wind, it takes only 5 hours. find the rate of the airplane with no wind. find the rate of the wind\r \n" ); document.write( "\n" ); document.write( "Let the ground speed be x \n" ); document.write( "And the wind speed be y\r \n" ); document.write( "\n" ); document.write( "AGAINST WIND \n" ); document.write( "Distance = 900 miles. \n" ); document.write( "Distance = Rate * time \n" ); document.write( "900= (x-y)*6 \n" ); document.write( "WITH WIND\r \n" ); document.write( "\n" ); document.write( "Distance = 900 miles. \n" ); document.write( "Distance = Rate * time \n" ); document.write( "900= (x+y)*5\r \n" ); document.write( "\n" ); document.write( "6x-6y=900 \n" ); document.write( "x-y= 150 \n" ); document.write( "5x+5y=900 \n" ); document.write( "x+y=180\r \n" ); document.write( "\n" ); document.write( "x-y= 150 \n" ); document.write( "x+y=180\r \n" ); document.write( "\n" ); document.write( "2x=330 \n" ); document.write( "x= 165 mph = ground speed ( With no wind )\r \n" ); document.write( "\n" ); document.write( "y= 15\r \n" ); document.write( "\n" ); document.write( "The ground speed of the plane is 165 mph and wind speed = 15 mph\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |