document.write( "Question 264867: The side of a cube is decreased by 50%. By how much does the volume decrease?
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Algebra.Com's Answer #194887 by Theo(13342)\"\" \"About 
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the volume of a cube is equal to s^3 = s*s*s\r
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\n" ); document.write( "\n" ); document.write( "if you halve the volume, then the volume of the cube becomes (.5*s)^3.\r
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\n" ); document.write( "\n" ); document.write( "(.5*s)^3 is the same as (.5)^3 * (s)^3 = .125*s^3.\r
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\n" ); document.write( "\n" ); document.write( ".125 * 100% = 12.5%\r
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\n" ); document.write( "\n" ); document.write( "The volume of the cube becomes 12.5% of the original volume.\r
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\n" ); document.write( "\n" ); document.write( "The question is:\r
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\n" ); document.write( "\n" ); document.write( "By how much does the volume decrease?\r
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\n" ); document.write( "\n" ); document.write( "If you go from 100% of the volume to 12.5% of the volume, you have decreased by 87.5% of the original volume.\r
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\n" ); document.write( "\n" ); document.write( "your answer would be selection E (87.5%).\r
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\n" ); document.write( "\n" ); document.write( "As an example:\r
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\n" ); document.write( "\n" ); document.write( "Assume the side of the cube is 4.\r
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\n" ); document.write( "\n" ); document.write( "The volume is 4^3 = 4*4*4 = 64\r
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\n" ); document.write( "\n" ); document.write( "Take half the side of the cube to get 2.\r
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\n" ); document.write( "\n" ); document.write( "The volume of the cube is now 2^3 = 2*2*2 = 8.\r
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\n" ); document.write( "\n" ); document.write( "8/64 = 1/8 = .125 * 100% = 12.5%.\r
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\n" ); document.write( "\n" ); document.write( "The volume has decreased from 64 to 8 which is a decrease of 64 - 8 = 56.\r
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\n" ); document.write( "\n" ); document.write( "56 / 64 = .875 * 100% = a decrease of 87.5% of the original volume.\r
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