document.write( "Question 32330: I need help with this problem \r
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document.write( "The inverse of y=6x^2-13x \r
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document.write( "I got Y=13+or-square root 145 all over 2 \n" );
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Algebra.Com's Answer #19488 by stanbon(75887) ![]() You can put this solution on YOUR website! Interchange x and y to get: \n" ); document.write( "x=6y^2-13y \n" ); document.write( "Solve for \"y\" \n" ); document.write( "Rewrite in quadratic form: \n" ); document.write( "6y^2-13y-x=0 \n" ); document.write( "Use the quadratic formula to get: \n" ); document.write( " y= [13+sqrt(13^2+4(6)x)]/12 and also \n" ); document.write( " y= [13-sqrt(13^2+4(6)x)]/12 \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |