document.write( "Question 264818: Two planes depart from the same place at 2pm. One plane flies south at a speed of 376km/hr, and the other flies west at a speed of 648km/hr. How far apart are the airplanes at 5:30PM? \n" ); document.write( "
Algebra.Com's Answer #194870 by mananth(16946)\"\" \"About 
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Two planes depart from the same place at 2pm. One plane flies south at a speed of 376km/hr, and the other flies west at a speed of 648km/hr. How far apart are the airplanes at 5:30PM?\r
\n" ); document.write( "\n" ); document.write( "distance traveled by first plane to south in 3.5 hours= 376*3.5=1316
\n" ); document.write( "distance traveled by first plane to west in 3.5 hours= 648*3.5=2268\r
\n" ); document.write( "\n" ); document.write( "they are traveling at right angles\r
\n" ); document.write( "\n" ); document.write( "so apply pythagoras theorem\r
\n" ); document.write( "\n" ); document.write( "for finding the hypotenuse = distance\r
\n" ); document.write( "\n" ); document.write( "(1316)^2 +(2268)^2 = 1731856 + 5225796 = (6875680)^2 = 2622.15
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