document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33052>Question 33052</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Would someone check to see if I did this correctly? Thank you in advance<BR>\n" );
document.write( "  Solve for x:<BR>\n" );
document.write( "2(x + 1) > 12\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Simplify left side and right side to get:<BR>\n" );
document.write( "2x + 1=12-3<BR>\n" );
document.write( "2 + 1 + x = 12<BR>\n" );
document.write( "x = 9<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19487 by </B><A HREF=/tutors/aboutme.mpl?userid=babyblue87><B>babyblue87(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=babyblue87><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19487\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2(x + 1) > 12<BR>\n" );
document.write( "2x + 2 > 12<BR>\n" );
document.write( "2x + (2 - 2) > (12 - 2)<BR>\n" );
document.write( "2x > 10<BR>\n" );
document.write( "(2/2) > 10/2<BR>\n" );
document.write( "x > 5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );