document.write( "Question 264733: I hope that I can describe this well enough. I have a problem with a graph that contains two parallel lines. Line 1 has the equation y=2x+1 and Line 2 contains the point (0,-2). The problem is asking me to find point P in Line 2. What I know is that P is (?, 0). I've tried (4,0), but the computer program I'm working with doesn't like that answer. Any help would be greatly appreciated! \n" ); document.write( "

Algebra.Com's Answer #194839 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Any 2 lines that are parallel have the same slope.
\n" ); document.write( "The 1st line, $\"y+=+2x+%2B+1\"$ , is in the form
\n" ); document.write( " $\"y+=+mx+%2B+b\"$ ,
\n" ); document.write( "where $\"m\"$ is the slope, so
\n" ); document.write( "the slope of both lines must be $\"2\"$
\n" ); document.write( "given:
\n" ); document.write( "Line 2 goes through (0,-2)
\n" ); document.write( "I can plug this (x,y) into $\"y+=+mx+%2B+b\"$ , $\"m+=+2\"$
\n" ); document.write( "and I can find $\"b\"$
\n" ); document.write( " $\"-2+=+2%2A0+%2B+b\"$
\n" ); document.write( " $\"b+=+-2\"$
\n" ); document.write( "Now I know line 2 is $\"y+=+2x+-+2\"$
\n" ); document.write( "Now I can find (x,0)
\n" ); document.write( " $\"0+=+2x+-+2\"$
\n" ); document.write( " $\"2x+=+2\"$
\n" ); document.write( " $\"x+=+1\"$
\n" ); document.write( "So the point asked for is P(1,0)\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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