document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33015>Question 33015</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For some reason I can not set up these kind of word problems:\r<BR>\n" );
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document.write( "According to data from the US dept of defense and congressional research service, the estimated annual cost y (in thousands of dollars) per active duty service member in the us armed forces in year x is given by the equation:\r<BR>\n" );
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document.write( "6000x-2000y+136000=0 (4< x < 18)\r<BR>\n" );
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document.write( "where x=4 corresponds to 1994. find the year in which the estimated annual cost per service member is (a) $92,000  (b) 110,000\r<BR>\n" );
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document.write( "-i have tried setting up the equation by substituting 4 for x and then entering both equations in my TI 83. I believe it's an intersection answer between two equations, however, i am not getting anywhere and i have attemped four other similar questions hoping i something would click. There are also no examples in the text i am using to assist.  Thank you for any help you may provide.\r<BR>\n" );
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document.write( "erin mcavoy </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19481 by </B><A HREF=/tutors/aboutme.mpl?userid=xcentaur><B>xcentaur(357)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=xcentaur><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19481\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6000x-2000y+136000=0 (4< x < 18)<BR>\n" );
document.write( "where x=4 corresponds to 1994<BR>\n" );
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document.write( "It reduces to y=3x+68.<BR>\n" );
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document.write( "x=4,y=3(4)+68=12+68=80<BR>\n" );
document.write( "x=5,y=3(5)+68=15+68=83<BR>\n" );
document.write( "x=6,y=86<BR>\n" );
document.write( "x=7,y=89<BR>\n" );
document.write( "x=8,y=92------------->(a)<BR>\n" );
document.write( "x=9,y=95<BR>\n" );
document.write( "x=10,y=98<BR>\n" );
document.write( "x=11,y=101<BR>\n" );
document.write( "x=12,y=104<BR>\n" );
document.write( "x=13,y=107<BR>\n" );
document.write( "x=14,y=110----------->(b)<BR>\n" );
document.write( "x=15,y=113<BR>\n" );
document.write( "x=16,y=116<BR>\n" );
document.write( "x=17,y=119<BR>\n" );
document.write( "x=18,y=122<BR>\n" );
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document.write( "If you substitute x=0,we get y=68.Multiply this by 1000 and we get a credible figure,considering it as 1990. Then for x=18,y=122 ie in the year 2008, a figure of $122000 seems to make sense.<BR>\n" );
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document.write( "That would make 1998 and 2004 your answers,though of course we have no logical reasoning to back this up.<BR>\n" );
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document.write( "If this is a valid question,and you do manage to solve this,drop a mail at:<BR>\n" );
document.write( "xcentaur[at]hotmail[dot]com<BR>\n" );
document.write( "Hope this helps,<BR>\n" );
document.write( "xC </SPAN>\n" );
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