document.write( "Question 264507: one number is four greater than another number when three times the smaller number is added to twice the larger number the result is 43.\r
\n" ); document.write( "\n" ); document.write( "Could you please give me the method to work it out i know the answer is 7 i just don't know how to get there.
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Algebra.Com's Answer #194758 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
let x = \"one number\"
\n" ); document.write( "let y = \"another number\"
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( ":
\n" ); document.write( "\"one number is four greater than another number\"
\n" ); document.write( "x = y + 4
\n" ); document.write( ":
\n" ); document.write( "\"when three times the smaller number is added to twice the larger number the result is 43\"
\n" ); document.write( "3y + 2x = 43
\n" ); document.write( ":
\n" ); document.write( "Replace x with (y+4), derived from the 1st statement
\n" ); document.write( "3y + 2(y+4) = 43
\n" ); document.write( "3y + 2y + 8 = 43
\n" ); document.write( "5y = 43 - 8
\n" ); document.write( "5y = 35
\n" ); document.write( "y = \"35%2F5\"
\n" ); document.write( "y = 7
\n" ); document.write( ":
\n" ); document.write( "I'll let you find x
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