document.write( "Question 264546: the line y=2x-2 meets the circle (x-2)^2 + (y-2)^2 =20 at A and B. coordinates of A and B are, (0,-2) and (4,6). show that AB is a diameter of the circle. thank you would be so helpful if you could help, showing how you got the answer! thankyou \n" ); document.write( "

Algebra.Com's Answer #194753 by Alan3354(69443) $\"\"$ $\"About$

You can put this solution on YOUR website!
If you accept that they intersect at A and B, then all you need to show is that the distance from A to B is the diameter.
\n" ); document.write( " $\"r%5E2+=+20\"$ so $\"d%5E2+=+80\"$
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\n" ); document.write( "The square of the distance from A to B is
\n" ); document.write( " $\"diffy%5E2+%2B+diffx%5E2\"$
\n" ); document.write( "= $\"4%5E2+%2B+8%5E2\"$
\n" ); document.write( "= 80
\n" ); document.write( "------
\n" ); document.write( "It's the same length as the diameter, so it's thru the center of the circle.
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\n" ); document.write( "It was stated that A and B are on the circle and the line, so no proof of that was done.
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