document.write( "Question 264541: PLEASE HELP ME SOLVE THIS PROBLEMS: in the period of a year, an investor lost twice as much as he gained. if he origanlly had 10,000 and now has 6,000, what amount did he gain and what did he lose? \n" ); document.write( "
Algebra.Com's Answer #194748 by jim_thompson5910(35256)\"\" \"About 
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If he had $10,000 and gained 'x' dollars, then lost twice that at 2x dollars, then he would then have \"10000%2Bx-2x=10000-x\" dollars. Set this equal to 6,000 to get \"10000-x=6000\". Now simply solve for 'x' to find out how much he gained. Double that figure to find out how much he lost. \n" ); document.write( "
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