document.write( "Question 264531: simplify by taking roots of the numerator and the denominator.Assume all expressions under the radicals represent positive numbers.\r
\n" ); document.write( "\n" ); document.write( "cubed rt of 512x^5/y^3\r
\n" ); document.write( "\n" ); document.write( "please help....
\n" ); document.write( "

Algebra.Com's Answer #194741 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"root%283%2C%28512x%5E5%29%2F%28y%5E3%29%29\" Start with the given expression.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"root%283%2C512x%5E5%29%2Froot%283%2Cy%5E3%29\" Break up the root.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"root%283%2C8%5E3x%5E5%29%2Froot%283%2Cy%5E3%29\" Rewrite 512 as \"8%5E3\" (since \"512=8%5E3\")\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"root%283%2C8%5E3x%5E3x%5E2%29%2Froot%283%2Cy%5E3%29\" Rewrite \"x%5E5\" as \"x%5E3x%5E2\" (since \"x%5E5=x%5E3x%5E2\")\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"root%283%2C8%5E3%29root%283%2Cx%5E3%29root%283%2Cx%5E2%29%2Froot%283%2Cy%5E3%29\" Break up the root in the numerator.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%288%2Aroot%283%2Cx%5E3%29root%283%2Cx%5E2%29%29%2Froot%283%2Cy%5E3%29\" Evaluate the cube root \"8%5E3\" to get 8. Remember the cube root of anything cubed is simply that original expression. In other words, \"root%283%2Cx%5E3%29=x\". This is why everything was broken down into parts dealing with cubes.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%288x%2Aroot%283%2Cx%5E2%29%29%2Froot%283%2Cy%5E3%29\" Evaluate the cube root \"x%5E3\" to get 'x'.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%288x%2Aroot%283%2Cx%5E2%29%29%2Fy\" Evaluate the cube root \"y%5E3\" to get 'y'.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So \"root%283%2C%28512x%5E5%29%2F%28y%5E3%29%29=%288x%2Aroot%283%2Cx%5E2%29%29%2Fy\" where \"y%3C%3E0\"
\n" ); document.write( "
\n" );