document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=264459>Question 264459</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the perimeter and area of a right trianlge if the shortest side is 24mm. and the longest side is 40mm.  Please show me all the work and include the units.\r<BR>\n" );
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document.write( "Thanks so much... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #194708 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=194708\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A^2+B^2=C^2<BR>\n" );
document.write( "24^2+40^2=C^2<BR>\n" );
document.write( "c^2=576+1600<BR>\n" );
document.write( "C^2=2176<BR>\n" );
document.write( "c=46.65 mm<BR>\n" );
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document.write( "46.65+40+24=110.65 mm<BR>\n" );
document.write( "P=110.65 mm<BR>\n" );
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document.write( "A=(LW)/2<BR>\n" );
document.write( "A=(40*24)/2<BR>\n" );
document.write( "A=480 cu mm </SPAN>\n" );
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