document.write( "Question 247981: This is a quadratic word problem. \r
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document.write( "A garden is to be laid out in such a way that 3 rectangular sections are created by fences. If the total amount of fencing available is 200 ft., find the dimensions that will maximize the total area. \n" );
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Algebra.Com's Answer #194672 by Alan3354(69443) You can put this solution on YOUR website! A garden is to be laid out in such a way that 3 rectangular sections are created by fences. If the total amount of fencing available is 200 ft., find the dimensions that will maximize the total area. \n" ); document.write( "--------------- \n" ); document.write( "I don't know why Tiff is here if she can't offer assistance. \n" ); document.write( "Anyway, \n" ); document.write( "The 200 feet of fence will be in 6 pieces. Call W the width of 2 pieces, and L the length of the 4 pieces. \n" ); document.write( "2L + 4W = 200 \n" ); document.write( "The total area is L*W \n" ); document.write( "2L + 4W = 200 --> L + 2W = 100 --> L = 100 - 2W \n" ); document.write( "Sub for L in the 2nd eqn \n" ); document.write( "Area = L*W \n" ); document.write( "Area = W*(100 - 2W) = 100W - 2W^2 \n" ); document.write( "Find W to maximize the area \n" ); document.write( "It's a parabola, and the max is at the vertex. \n" ); document.write( "The vertex is as W = -b/2a = -100/-4 \n" ); document.write( "W = 25 feet \n" ); document.write( "--------- \n" ); document.write( "L = 50 feet \n" ); document.write( " \n" ); document.write( " |