document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=264388>Question 264388</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 8.	A mixture with 60% orange content, what % of water should be added to make this mixture as 40%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #194656 by </B><A HREF=/tutors/aboutme.mpl?userid=vksarvepalli><B>vksarvepalli(154)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vksarvepalli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=vksarvepalli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=194656\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let there is 100 ml of original solution\r<BR>\n" );
document.write( "\n" );
document.write( "in that there is 60% that is 60 ml of orange content\r<BR>\n" );
document.write( "\n" );
document.write( "now suppose x ml of water is added \r<BR>\n" );
document.write( "\n" );
document.write( "so total it is 100+x ml and orange content is 60 ml\r<BR>\n" );
document.write( "\n" );
document.write( "now this 60 ml should constitute 40% of 100+x\r<BR>\n" );
document.write( "\n" );
document.write( "60=(40/100)(100+x)\r<BR>\n" );
document.write( "\n" );
document.write( "60=40+.4x\r<BR>\n" );
document.write( "\n" );
document.write( ".4x=20\r<BR>\n" );
document.write( "\n" );
document.write( "x=50 ml\r<BR>\n" );
document.write( "\n" );
document.write( "so 50% of water should be added </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );