document.write( "Question 264388: 8. A mixture with 60% orange content, what % of water should be added to make this mixture as 40%? \n" ); document.write( "

Algebra.Com's Answer #194652 by drk(1908) $\"\"$ $\"About$

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This is a mixture problem. we can set up a table based on given information
\n" ); document.write( "liquid . . . . . . % . . . . . . L . . . . . . .%L
\n" ); document.write( "orange. . . . . .60 . . . . . x . . . . . . .60x
\n" ); document.write( "water. . . . . . . 0 . . . . . . y. . . . . . . 0y
\n" ); document.write( "mixture . . . . . 40 . . . . . x+y. . . . .40x + 40y
\n" ); document.write( "Looking at the third column, we get
\n" ); document.write( " $\"60x+=+40x+%2B+40y\"$
\n" ); document.write( "or
\n" ); document.write( " $\"20x+=+40y\"$
\n" ); document.write( "dividing, we get
\n" ); document.write( " $\"x+=+2y\"$
\n" ); document.write( "This means what ever the amount of orange juice is, the amount of water must be twice that.
\n" ); document.write( "we don't have enough information to answer with actual hard numbers. \n" ); document.write( "

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