document.write( "Question 264314: How many odd, perfect-square factors does the number 2(4th) x 3(6th) x 5(10th) x 7(9th) have? numbers in ( ) are powers. \n" ); document.write( "
Algebra.Com's Answer #194622 by JBarnum(2146)\"\" \"About 
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How many odd, perfect-square factors does the number 2(4th) x 3(6th) x 5(10th) x 7(9th) have? numbers in ( ) are powers.\r
\n" ); document.write( "\n" ); document.write( "list them is easiest way to visually see the squares
\n" ); document.write( "2^4
\n" ); document.write( "(2x2)(2x2) so 2[]s
\n" ); document.write( "3^6
\n" ); document.write( "(3x3)(3x3)(3x3) so 3[]s
\n" ); document.write( "5^10
\n" ); document.write( "(5x5)(5x5)(5x5)(5x5)(5x5) so 5[]s
\n" ); document.write( "7^9
\n" ); document.write( "(7x7)(7x7)(7x7)(7x7)(7) so 4[]s\r
\n" ); document.write( "\n" ); document.write( "2+3+5+4= 14 perfect squares
\n" ); document.write( "2 of the squares are even so there are 12 odd perfect squares
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