document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=264309>Question 264309</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am working with systems of Linear Equations. Confused. can you show me step by step how to solve \r<BR>\n" );
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document.write( " -2x + y = 1 and 3x + y = 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #194602 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=194602\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "The best way to do this is multiply the equation by -1 so to cancel out the y's<BR>\n" );
document.write( "-2x(-1) + y(-1) = 1(-1) which gives us:<BR>\n" );
document.write( "2x-y=-1 Now add this to the second equation: <BR>\n" );
document.write( "3x + y = 1<BR>\n" );
document.write( "And we get:<BR>\n" );
document.write( "5x=0 Divide both sides by 5 and we get:<BR>\n" );
document.write( "x=0<BR>\n" );
document.write( "Now plug this into either original equation to find out \"y\"<BR>\n" );
document.write( "-2(0) + y = 1 Do the calculations and we have:<BR>\n" );
document.write( "y=1<BR>\n" );
document.write( "There we go the solutions will work in either equation now. <BR>\n" );
document.write( "RJ <BR>\n" );
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document.write( "www.math-unlock.com </SPAN>\n" );
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