document.write( "Question 264295: y=2x
\n" ); document.write( "x+y=12 What is the answer in (x,y) form\r
\n" ); document.write( "\n" ); document.write( "y=1/3x+6
\n" ); document.write( "3y-x=24 What is the answer in (x,y) form\r
\n" ); document.write( "\n" ); document.write( "3x+2y=13
\n" ); document.write( "5x=2y+11 What is the answer in (x,y) form\r
\n" ); document.write( "\n" ); document.write( "6x-2y=6
\n" ); document.write( "x+2y=8 What is the answer in (x,y) form
\n" ); document.write( "

Algebra.Com's Answer #194598 by JBarnum(2146)\"\" \"About 
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y=2x
\n" ); document.write( "x+y=12 What is the answer in (x,y) form\r
\n" ); document.write( "\n" ); document.write( "y=1/3x+6
\n" ); document.write( "3y-x=24 What is the answer in (x,y) form\r
\n" ); document.write( "\n" ); document.write( "3x+2y=13
\n" ); document.write( "5x=2y+11 What is the answer in (x,y) form\r
\n" ); document.write( "\n" ); document.write( "6x-2y=6
\n" ); document.write( "x+2y=8 What is the answer in (x,y) form\r
\n" ); document.write( "\n" ); document.write( "___________________________________________
\n" ); document.write( "These are all substitution/elimination problems\r
\n" ); document.write( "\n" ); document.write( "y=2x
\n" ); document.write( "x+y=12 We know what \"y\" equals so put \"2x\" in place of the \"y\" in second equation
\n" ); document.write( "x+(2x)=12 add common terms
\n" ); document.write( "3x=12 divide by 3
\n" ); document.write( "x=4
\n" ); document.write( "Now we know x=4 so replace \"x\" with \"4\" in the first equation
\n" ); document.write( "y=2x
\n" ); document.write( "y=2(4)
\n" ); document.write( "y=8
\n" ); document.write( "Now we know that y=4 so to put it in (x,y) form just replace the letters with the numbers (4,8)
\n" ); document.write( "--------------------------------\r
\n" ); document.write( "\n" ); document.write( "y=1/3x+6
\n" ); document.write( "3y-x=24
\n" ); document.write( "Im un able to answer this question completely as I dont know if the first equation is y=(1/3)x +6 or y=1/(3x+6) there will be completely different answers so please be specific when writing the problem.
\n" ); document.write( "if I had to guess it would be y=(1/3)x +6.
\n" ); document.write( "im going to use the elimination methad as its by far easier then to substitute with fractions.
\n" ); document.write( "y-(1/3)x=6 id multiply this line by -3 so i can eliminate the \"y\"
\n" ); document.write( "3y-x=24
\n" ); document.write( "-3y+x=-24 well as we can see these 2 equasions completely cancel each other out so the only possible answers can be (8,0) or(0,-24).due to the cancelation one variable must be 0.
\n" ); document.write( "-----------------\r
\n" ); document.write( "\n" ); document.write( "3x+2y=13
\n" ); document.write( "5x=2y+11
\n" ); document.write( "Id start with the bottom equation to rearange it use the elimination method
\n" ); document.write( "5x=2y+11 => 5x-2y=11\r
\n" ); document.write( "\n" ); document.write( "3x+2y=13
\n" ); document.write( "5x-2y=11 add vertically
\n" ); document.write( "8x+0=24
\n" ); document.write( "x=3
\n" ); document.write( "Plug x=3 into one of the equations to find \"y\"
\n" ); document.write( "3(3)+2y=13
\n" ); document.write( "9+2y=13
\n" ); document.write( "2y=4
\n" ); document.write( "y=2
\n" ); document.write( "(x,y)=(3,2)
\n" ); document.write( "------------------
\n" ); document.write( "
\n" ); document.write( "6x-2y=6
\n" ); document.write( "x+2y=8
\n" ); document.write( "add these vertically
\n" ); document.write( "7x+0=14
\n" ); document.write( "x=2
\n" ); document.write( "Plug x=2 into one of the equations to find \"y\"
\n" ); document.write( "(2)+2y=8
\n" ); document.write( "2y=6
\n" ); document.write( "y=3
\n" ); document.write( "(x,y)=(2,3)
\n" ); document.write( "
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