document.write( "Question 264297: 3a^2+a-10>0
\n" ); document.write( "we are using delta = b^2-4*a*c
\n" ); document.write( "my solution to this equation is [-5/2,3} the book says the solution is (-oo,-2)U(5/3,oo)
\n" ); document.write( "please help me find what I am doing wrong
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Algebra.Com's Answer #194596 by mananth(16946)\"\" \"About 
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3a^2+a-10>0
\n" ); document.write( "we are using delta = b^2-4*a*c
\n" ); document.write( "my solution to this equation is [-5/2,3} the book says the solution is (-oo,-2)U(5/3,oo)
\n" ); document.write( "please help me find what I am doing wrong\r
\n" ); document.write( "\n" ); document.write( "3a^2+a-10>0
\n" ); document.write( "3a^2+6a-5a-10>0\r
\n" ); document.write( "\n" ); document.write( "3a(a+2)-5(a+2)>0\r
\n" ); document.write( "\n" ); document.write( "(a+2)(3a-5)>0 \r
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